-1/(x^2+2x-35)

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Solution for -1/(x^2+2x-35) equation: 


D( x )

x^2+2*x-35 = 0

x^2+2*x-35 = 0

x^2+2*x-35 = 0

x^2+2*x-35 = 0

DELTA = 2^2-(-35*1*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)-2)/(1*2) or x = (-144^(1/2)-2)/(1*2)

x = 5 or x = -7

x in (-oo:-7) U (-7:5) U (5:+oo)

-1/(x^2+2*x-35) = 0

x^2+2*x-35 = 0

x^2+2*x-35 = 0

DELTA = 2^2-(-35*1*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)-2)/(1*2) or x = (-144^(1/2)-2)/(1*2)

x = 5 or x = -7

(x+7)*(x-5) = 0

-1/((x+7)*(x-5)) = 0

x belongs to the empty set

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